f(2)=0.016(2)^(2)+0.124(2)+0.787

Solution for f(2)=0.016(2)^(2)+0.124(2)+0.787 equation:

f(2)=0.016(2)^(2)+0.124(2)+0.787

We move all terms to the left:

f(2)-(0.016(2)^(2)+0.124(2)+0.787)=0

We add all the numbers together, and all the variables

f^2-0.91146244=0

a = 1; b = 0; c = -0.91146244;
Δ = b2-4ac
Δ = 02-4·1·(-0.91146244)
Δ = 3.64584976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.64584976}}{2*1}=\frac{0-\sqrt{3.64584976}}{2}
=-\frac{\sqrt{}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.64584976}}{2*1}=\frac{0+\sqrt{3.64584976}}{2}
=\frac{\sqrt{}}{2}
$